Design View: By JFLAP Software Concept : aaabbb Case1: XaaYbb Case2:XXaYYb Case3:XXXYYY Case 1: Read first 'a' and replace it by 'X' Then read first 'b' and replace it as 'Y' What i am doing is .....Meaning of a^n b^n is " Equal no: of a's must followed by equal no: of b's " In Case 1 : I read first 'a' and First 'b'. Before reading Second 'b'....Should read Second 'a' .... Then continue the steps.....Finally 'B' reads....Machine will stop... Transitions concept will continue ......
CS 09 506 Theory Of Computation